| CD | ||
https://omj.edu.pl/uploads/attachments/3etap18r.pdf
Mam pytanie, jak w drugim zadaniu obliczyli z Talesa, że | ? | |
| AB |
| x | x | 5 | ||||
sin4 | +cos4 | = | ||||
| 3 | 3 | 8 |
| x | x | x | x | 5 | ||||||
(sin2 | +cos2 | )2−2sin2 | *cos2 | = | ||||||
| 3 | 3 | 3 | 3 | 8 |
| x | x | 5 | ||||
1−2sin2 | *cos2 | = | ||||
| 3 | 3 | 8 |
| x | x | 3 | ||||
−2sin2( | )*cos2( | )=− | ||||
| 3 | 3 | 8 |
| x | x | 3 | ||||
sin2( | )*cos2( | )= | ||||
| 3 | 3 | 16 |
| x | x | 3 | ||||
(sin | *cos | )2= | ||||
| 3 | 3 | 16 |
| 1 | 2 | 3 | |||
sin2( | x}= | ||||
| 4 | 3 | 16 |
| 2 | 3 | |||
sin2( | x)= | |||
| 3 | 4 |
| 2 | √3 | 2 | √3 | |||||
sin | x= | lub sin | x=− | |||||
| 2 | 2 | 3 | 2 |
| 2 | π | |||
sin | x=sin | |||
| 3 | 3 |
| 2 | π | 2 | π | ||||
x= | +2π*k lub | x=π− | +2π*k (policze | ||||
| 3 | 3 | 3 | 3 |
| π | ||
z= 1+cosα + isinα (0≤α< | ) | |
| 2 |