| x+2 | ||
f(x)= | ||
| √1−x2 |
| log26*log36 | |
| log26+log36 |
| log26*2 | ||
doszedłem do postaci: | i nie wiem co dalej robic ![]() | |
| log26+2 |
| (n+1)!+(n+2)! | |
| n! |
| x+1 | ||
Dla funkcji f(x) = | wyznaczyć | |
| x−1 |
| 1 | ||
√ 4span style="font-family:times; margin-left:1px; margin-right:1px">1x + | + √4 − log20,5x | |
| lnx |
?
| 1 | ||
f(x) = x − | ||
| atctgx |
| x−3dx | x | 3 | ||||
∫ | =∫ | dx−∫ | dx | |||
| 2−x | 2−x | 2−x |