| x(x+1) | 2 | x(x+1)−2 | ||||
lim [ | − | ]=lim [ | ] | |||
| x4−1 | x4−1 | (x−1)(x+1)(x2+1) |
| 1 | ||
sin4−cos4=log | (m+4) | |
| 2 |
| 3i | ||
2z2 + 7iz − 6 = 0 ⇔ z1 = −2i, z2 = − | ||
| 2 |
| 1 − log235 | 1 | ||
+ 1 = | |||
| log516 + log25 −2 | log22 |
| log √2 | |
+ 813log2 3 = | |
| 2 log 4 − log 8 |
| log 212 | ||
+ 813log2 3 = | ||
| log(22)2 − log 23 |
| log 212 | |||||||||||
+ 813log2 3 | |||||||||||
|
| x2y | ||
A={ | : x,y ≥0}. | |
| x4 + 2y2 + 3 |
| dv | dv | |||
Bo w jednym zadaniu spotkałem sie z zapisem a = | a w drugim as= | as to | ||
| dt | dt |
| 1 | 2 | n | ||||
lim n→∞( | + | + ... + | ) | |||
| 1+n2 | 2+2n | n+n2 |
| 3x−1 | ||
√ | >1 | |
| 2−x |