| 2 | ||
0≤ | ≤4 | |
| x+2 |
| 1 | ||
7) | − cosα = sinα * tgα
| |
| cosα |
| 1 | ||
9) (1 + sinα)( | − tgα) = cosα
| |
| cosα |
| sinα | 1 + cosα | 2 | ||||
10) | + | = | ||||
| 1 + cosα | sinα | sinα |
| 1 | ||
11) (tgα + ctgα)2 = | ||
| sin2α * cos2α |
| 1 | 1 | |||
14) ( | − | )(sinα + cosα) = ctgα − tgα
| ||
| sinα | cosα |
| 1 − tg2α | ||
15) 1 − 2sin2α = | ||
| 1 + tg2α |
| 2 | ||
16) | − 1 = 1 + 2ctg2α | |
| sin2α |
| 1 | ||
7) | − cosα = sinα * tgα
| |
| cosα |
| 1 | ||
9) (1 + sinα)( | − tgα) = cosα
| |
| cosα |
| sinα | 1 + cosα | 2 | ||||
10) | + | = | ||||
| 1 + cosα | sinα | sinα |
| 1 | ||
11) (tgα + ctgα)2 = | ||
| sin2α * cos2α |
| 1 | 1 | |||
14) ( | − | )(sinα + cosα) = ctgα − tgα
| ||
| sinα | cosα |
| 1 − tg2α | ||
15) 1 − 2sin2α = | ||
| 1 + tg2α |
| 2 | ||
16) | − 1 = 1 + 2ctg2α | |
| sin2α |
| 1 | 1 | |||
USUŃ NIEWYMIERNOŚĆ | oraz | |||
| √2+√3+√5 | 1+√2+√5 |
| √831744+√4624 | ||
OBLICZ √9960336−√4562496−2* | ||
| √9604 |