OSTROSŁUP sebo200100: Bardzo proszę o pomoc z tymi zadaniami! z góry dziękuję zamieszczam zdjęcie zadań: http://img831.imageshack.us/img831/745/img011yo.jpg

dero2005: 1) d = 8 cm

	d√2
a =		= 4√2 cm
	2

H
	= tg 60o = √3
d2

	d√3
H =		= 4√3 cm
	2

	128
V = 13a2*H =		*√3 cm3
	3

dero2005: 2) a = 16 cm

H
	= tg 60o = √3
a2

H = ^a₂√3 = 8√3 cm h_s = √H² + (^a₂)² = √(8√3)² + 8² = 16 cm P_b = 2*a*h_s = 2*16*16 = 512 cm² P_p = a² = 16² = 256 cm² P_c = P_b + P_p = 512 + 256 = 768 cm² V = ¹₃P_p*H = ¹₃*256*8√3 = ²⁰⁴⁸₃*√3 cm³

dero2005: 3) h_s = 20 cm

H
	= sin 30o = 12
hs

	hs
H =		= 10 cm
	2

(^a₂)² = h_s² − H² → a = 20√3 cm P_b = 2*a*h_s = −−−−− P_p = a² = −−−−− P_c = P_p + P_b = −−−−− V = ¹₃*P_p*H = −−−−−−

dero2005: 4) l = 8 cm

H
	= cos 60o = 12
l

H = 4 cm (^d₂)² = l² − H² d = 8√3 cm

	d√2
a =		= 4√6
	2

P_p = a² = 96 cm² V = ¹₃P_p*H = 128 cm³

dero2005: H = 4 cm a = 6 cm (h_s)² = (^a₂)² + H² h_s = 5 cm P_b = 2*a*h_s = 2*6*5 = 60 cm² P_p = a² = 36 cm² P_c = P_b + P_p = 96 cm² V = ¹₃*P_p*H = ¹₃*36*4 = 48 cm³