| 3cos2α−sin2α | |
dzielilem przez cos2x i nie wychodzi prosze o | |
| sinα*cosα+cos2α |
| mx | m+2 | ||
+ | = x + 2√2 | ||
| m−2 | x |
| 1 | 2 | 3 | 4 | n√n3 + 2n2 + 3n + 4 | ||||||
limn√ | + | + | + | = lim | = | |||||
| n | n2 | n2 | n4 | n√n4 |
| n√n3 + 2n2 + 3n + 4 | ||
lim | = lim n√n3 + 2n2 + 3n + 4 | |
| n√n n√n n√n n√n |