14 | ||
o 4 a minownik zmniejszymy o 2 ,to otrzymamy | wartosci ulamka. Wyznacz ten ulamek | |
5 |
6x2+3x−7 | |
x2−9 |
1 | ||
(3√arcsin x2' = ((arcsin x*2)1/3)' = | * (arcsin x2)' = | |
3arcsin x2)2/3 |
1 | 1 | (1 | ||||
* | * (x2)' = | )2/3 * | ||||
3arcsin x2)2/3 | (√1−x2) | 3 arcsin x2 |
2x | ||
1/(√1−x2) * 2x = | ||
3(arcsinx2)2/3(√1−x2) |