| m+2 | ||
Wiedząc,że log324=m wykaż,że log1636= | ||
| 2(m−1) |
Pomożesz?
| 3log36 | 3log3(3•2) | 3(1+log32) | ||||
log1636=log1662= | = | = | ||||
| log316 | log324 | 4log32 |
| 2log36 | 2(1+log32) | 1+(m−1)/3 | 3+m−1 | ||||
= | = | = | |||||
| log316 | 4log32 | 2(m−1)/3 | 2(m−1) |
| m−1 | ||
log32= | ||
| 3 |
| log3(9*4) | 2+2log32 | 1+log32 | ||||
log1636= | = | = | ||||
| log316 | 4log32 | 2log32 |