| 2 | ||
log89= | log23 | |
| 3 |
| 1 | 1 | |||
a=log1218=log122+2log123= | +2 | |||
| log23+2 | 1+2log32 |
| 1 | 2log23 | 1+2log23 | ||||
a= | + | = | ||||
| log23+2 | log23+2 | log23+2 |
| 2 | ||
log89= | log23 | |
| 3 |
| log2 2*9 | 1+2log23 | |||
log1218= | = | = a | ||
| log24*3 | 2+log23 |
| 2a−1 | ||
zatem 1+2log23=alog23+2a ⇒ log23= | ||
| 2−a |
| 2(2a−1) | ||
to log89= | ||
| a−2 |
Nie wytrzymasz .
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |