| 1 | ||
f(x)= | ||
| √x2+x+3 |
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| 1 | 1 | 1 | 11 | |||||
[x2+x+3=(x+ | )2− | +3)=(x+ | )2+ | ] | ||||
| 2 | 4 | 2 | 4 |
| 1 | √11 | √11 | ||||
[(x+ | )= | t, dx= | dt] | |||
| 2 | 2 | 2 |
| 1 | √11 | |||
∫ | * | dt= | ||
| √114t2+114 | 2 |
| 1 | ||
=∫ | dt=ln|t+√t2+1|= podstaw za t i przekształć | |
| √t2+1 |