logarytm
ulka: a) log1/42?
b)Wiadomo, że log32=a. Oblicz log916.
9 mar 19:40
9 mar 19:46
ulka: Nadal nie rozumiem
9 mar 20:05
Janek191::
| | 1 | |
a) log14 2 = x ⇔ ( |
| ) x = 2 ⇔ (2−2)x= 2 ⇔ 2−2x = 21 ⇔ |
| | 4 | |
9 mar 20:10
Janek191::
b) log
3 2 = a
więc
| | 1 | |
log9 16 = log32 24 = |
| *4 log3 2 = 2 a |
| | 2 | |
| | 1 | |
Wzór: logaα b = |
| loga b |
| | α | |
oraz
log
a b
n = n* log
a b
9 mar 20:15