| p | ||
wyszło mi z pierwszego q* | ||
| log8 10 |
| log35 | log35 | |||
a) log5 = | = | |||
| log310 | log32 + log35 |
| 1 | 1 | 1 | ||||
log83 = p ⇔ | = p ⇔ | = p ⇔ log32 = | ... | |||
| log38 | 3log32 | 3p |
| q | 3pq | |||||||||
..... podstawiamy: log5 = | = | |||||||||
| 1 + 3pq |
| 49 | 49 | |||
b) .. ⇔ | + 5log54−1 ⇔ | + 5log54−1 = | ||
| 72log72 | 7log74 |
| 49 | 1 | 50 | ||||
+ | = | |||||
| 4 | 4 | 4 |