katasza: Oblicz: √3cosx-sinx=√2

Jakub: √3cosx - sinx = √2 /:2 (√3/2)cosx - (1/2)sinx = √2/2 cos(π/6)cosx - sin(π/6)sinx = cos45^o cos((π/6)+x) = cos(π/4) <-- to ze wzoru na 1543 π/6 +x = π/4 + k*2π x = π/4-π/6 +k*2π x = π/12 + k*2π