rozwiaz nierownosci
aga: x2−x−2>0
x2−x−6≤0
x2−1≥0
x2−x+2>0
25 lis 10:49
25 lis 11:35
aa: 1)
Δ=(−1)
2−4*1*(−2)=1+8=9
√Δ=3
x∊(−
∞,−1)v(2, +
∞)
25 lis 11:46
aa: 2)
x2−x−6≤0
Δ=1−4*1*(−6)=25 √25=5
x1=−2 x2=3
x∊<−2, 3>
25 lis 11:47
aa: x2−1≥0
(x−1)(x+1)≥0
x1=1 x2=−1
x∊(−∞ ,−1>v<1, +∞ )
25 lis 11:49