Oblicz x
Julia: sinx,sin2x,sin3x − ciąg arytmetyczny. Oblicz x
8 cze 16:11
M:
14 mar 10:03
Mei Lin:
| | sin(x)+sin(3x) | |
sin(2x)= |
| |
| | 2 | |
2sin(2x)=sin(x)+sin(3x)
| | 4x | | −2x | |
2sin(2x)=2sin |
| *cos |
| |
| | 2 | | 2 | |
2sin(2x)=2sin(2x)*cos(x)
2sin(2x)−2sin(2x)*cos(x)=0
2sin(2x)[1−cos(x)]=0
2sin(2x)=0
sin(2x)=0
2x=0+kπ k∊Z
lub
1−cos(x)=0
cos(x)=1
14 mar 10:49