?


| 1 | ||
− | (x − 1)(x + 3)(x + 5) = x2 + 2x − 3 | |
| 2 |
| −2 − 4 | ||
x1 = | = −3 | |
| 2 |
| −2 + 4 | ||
x2 = | = 1 | |
| 2 |
| 1 | ||
− | (x − 1)(x + 3)(x + 5) = (x − 1)(x + 3) | |
| 2 |
| 1 | ||
− | (x − 1)(x + 3)(x + 5) − (x − 1)(x + 3) = 0 | |
| 2 |
| 1 | 5 | |||
−(x − 1)(x + 3)( | x + | + 1) = 0 | ||
| 2 | 2 |
| 1 | 7 | |||
−(x − 1)(x + 3)( | x + | ) = 0 | ||
| 2 | 2 |
!