Oblicz
Basia: Oblicz
log22(4x)+log2x2−3=8
21 kwi 21:30
think: log22(4x) + log2x2 − 3 = 8
[log2(4x)]2 + 2log2x − 11 = 0
[log24 + log2x]2 + 2log2x − 11 = 0
[2 + log2x]2 + 2log2x − 11 = 0
4 + 4log2x + log22x + 2log2x − 11 = 0
log22x + 6log2x − 7 = 0
(log2x + 3)2 = 16
log2x + 3 = 4 v log2x + 3 = − 4
log2x = 1 v log2x = −7
x = 2 v x = 2−7
21 kwi 21:47
Basia: Dzięki za poomoc
21 kwi 21:58