oblicz Kaja:

	5
logx(3√3)−		= (logx√3)2
	4

M:

M:

Leszek: log_x(3√3 − ( log_x √3)² =5/4⇔log_x 3 +0,5log_x 3 −(0,5log_x 3)² =5/4 D: x ∊ (0,1)∪ (1 ,∞) niech log_x =t , t ∊R t +t/2 −t²/4 = 5/4⇒t² −6t +5 = 0 ,Δ_t = 16 , t₁ = 1 , t₂ =5 log_x 3 =1⇒x=3 ; log_x 3 = 5 ⇒ x = ⁵√3