Trygonometria
Daniel: 2sin2x + 2sinx = 2cosx + 1
12 mar 12:08
M:
24 mar 13:37
M:
9 cze 15:58
uczeń: 4sinx*cosx + 2 sinx = 2cosx +1
2sinx(2cosx +1) −(2cosx +1)=0
(2sinx−1)(2cosx +1) = 0
2sinx −1=0 lub 2cosx +1 =0 ⇔sinx = 1/2 lub cosx = −1/2
x = π/6 + 2kπ , x = 5π/6 + 2kπ , x = 2π/3 + 2kπ , x = 4π/3 + 2kπ
9 cze 17:31