h − wysokość walca
r − promień walca
R − promień kuli
h = R − 1
r = R − 2 R>2 r>0 żeby istniał walec
r2 + (h2)2 = R2
r2 + h24 = R2
4r2 + h2 = 4R2
4(R−2)2 + (R−1)2 = 4R2
−−−−−−−−−−−−−−−−−−−−−−−−itd
R2 − 18R + 17 = 0
Δ = 256 √Δ = 16
R1 = 1 → odrzucamy
R2 = 17 dm