calkowite l Pauliśka: Zadanie 26 X=4n−5*2n+1+25 X=(2²)ⁿ−5*2n+1+25 x=(2n−5)² X=(2²)ⁿ−5*2n+1+5² 2n−5ЄC bo, np. dla n=1 2¹−5=−3 Є C (a−b)²=a²−2ab+b²