| √x−5 | ||
Lim x−>25 | ||
| x−25 |
| √x2 +1−1 | ||
Lim x−>0 | ||
| √x2 +25 −5 |
| sin3x | ||
Lim x−>∞ | ||
| x |
| tg2x | ||
Lim x−>0 | ||
| tg3x |
| cosx | ||
Lim x−> 12π | ||
| x− 12π |
| cosx − cos 14π | ||
Lim x−> 14π | ||
| sinx − sin 14π |
| n+2 | ||
Lim n−>∞ ( | )n | |
| 2n+1 |
| ab−b2 | ||
a−b= | ||
| a+b |
| sin ax | ||
c i d) | −−> a gdy x−−>0 | |
| x |
| sin ax | a | ||
−−> | gdy x−−>0 | ||
| sin bx | b |
| 1 | ||
ostatnie w nawiasie masz 1/2 czyli ( | )n −−−> | |
| 2 |
| 1 | ||
to napisalem ,ze grancia tego w nawiasie jest | ||
| 2 |