Rozwiąż wyrażenie konrad_21: 6 ( 2x + y)^m+2 W = −−−−−−−−−−−−−−−− + 2y² 2x+y≠0 −3 (2x+y) ^m

M:

Miś Uszaty:

	6(2x+y)m+2
W(x)=		}+2y2=
	−3(2x+y)m

6(2x+y)m*(2x+y)2
	+2y2=−2(2x+y)2+2y2=
−3(2x+y)m

=−2(4x²+4xy+y²)+2y²= −8x²−8xy−2y²+2y²= =−8x²−8xy=−8x(x+y)

Nathan Grimes: Witam W pierwszym składniku (2x+y)m(2x + y)^m(2x+y)m się skraca: 6(2x+y)m−3(2x+y)m=6−3=−2\frac{6(2x + y)^m}{−3(2x + y)^m} = \frac{6}{−3} = −2−3(2x+y)m6(2x+y)m=−36=−2 Zatem: W=−2+2y2−3(2x+y)mW = −2 + \frac{2y²}{−3(2x + y)^m}W=−2+−3(2x+y)m2y2 czyli: W=−2−2y23(2x+y)mW = −2 − \frac{2y²}{3(2x + y)^m}W=−2−3(2x+y)m2y2 by: https://geometrydash-lite.io

Incerivers: The solution is very useful for https://slice-masters.io

emotionfencer: Addicted to Geometry Dash! The fast−paced gameplay and killer soundtrack keep me hooked for hours. One more try… just one more! https://geometry-game.io