w jogus: rozwiaz rownanie ²_x²−1+²_x−1=³_x+1+1

Maciek: Moment

Maciek:

2		2x+2		3x−3		x2−1
	+		−		−		=0
x2−1		x2−1		x2−1		x2−1

−x2−x+6
	=0
x2−1

(−x²−x+6)(x²−1)=0 Δ=1−4*(−1)*6 Δ=25 √Δ=5

	1+5		1−5
x1=		x2=
	−2		−2

x₁=−3 x₂=2 (−x²−x+6)(x²−1)=0 (x+3)(x−2)(x−1)(x+1)=0 x=−3 v x=2 v x=1 v x=−1