Efka: jak rozwiązać równanie: 2^x-2 + 2^x+1 - 2^x = 20

studencik85: 2^x:2^-2+2^x:2⁺1-2^x=20 2^x:(1/4)+2^x(2-1)=20 2^x:(1/4)+2^x=20 2^x*4+2^x=20 2^x(4+1)=20 2^x=4 2^x=2² x=2

studencik85: sorki znalazlem blad i tak to powino byc: 2^x:2²+ 2^x*2¹- 2^x=20 2^x:(4)+2x(2-1)=20 2^x:(4)+2x=20 2^x*(1/4)+2^x=20 2^x(1/4+1)=20 2^x(5/4)=20 2^x=20*(4/5) 2^x=16 2^x=2⁴ x=4