matematykaszkolna.pl
basia: log4 (x+3) - log4 (x-1)= 2- log4 8
2 gru 19:24
konopka: log4 (x+3)-log4 (x-1) = 2-log4 8 log4 {(x+3)/(x-1)] = log4 16 - log4 8 log4 [(x+3)/(x-1)] = log4 (16/8) log4[(x+3)/(x-1)] = log4 2 (x+3)/(x-1) = 2 (x+3) = 2(x-1) x+3= 2x - 2 x = 5
2 gru 20:20