wielomiany
peper: (x−1) (x2 + ax + 6) = (x+2) (x2 + 2x −b)
x3 +ax2 +6x −x2 − ax −6 = x3 + 2x2 −bx + 2x2 + 4x −2b
ax2−x2 + 6x − ax −6 = 4x2 +4x−bx − 2b
x2 (a−1 ) + x(6−a) − 6 = 4x2 + x (4 − b) − 2b
a−1 = 4
6−a = 4−b
6 = 2b
a=5
6−a=4−b
b=3
6−5 = 4−3
1=1
28 mar 18:51