oblicz
an: wiedząc że log27=a i log52=b oblicz 4a+(0,008)−b
24 mar 20:26
Eta:
| | 1 | | 1 | |
0,008= |
| = |
| = 5−3
|
| | 125 | | 53 | |
to: (0,008)
−b= (5
−3)
−b= 5
3b
4
a= 2
2a
d
logdc= c
2
2log27 + 5
3log52 = 2
log272+ 5
log523 = 49+8= 57
24 mar 20:41
an: dzięki wielkie.
24 mar 20:42
Eta: 
24 mar 20:44