| 4 | ||
Czy mógłbym prosić o pomoc? Będę wdzięczny  ;Rozwiąż równanie | = 2 – | |
| cos2 3x + 4 |
| 5 | ||
, gdzie x należy <0, π> | ||
| cos2 3x + 5 |
| 4 | 5 | |||
= 2− | ||||
| t+4 | t+5 |
| 4 | 2t+10−5 | |||
= | ||||
| t+4 | t+5 |
| π | ||
cos23x= 0 => cos3x=0 => 3x = k*π =? x= k* | , k€C
| |
| 3 |
| π | 2 | |||
odp; x= { 0, | , | π, π}
| ||
| 3 | 3 |
| π | π | π | ||||
cos3x =0 => 3 x = | + k*π => x = | +k* | , k€C
| |||
| 2 | 6 | 3 |