prosze o pomoc marysia 1992: rozwiaz rownienie f(x)=g(x) a) f(x)=x3−3x, g(x)=x b)f(x)=1/3x3+x+2, g(x)=4x+2 c)f(x)=4x3−x2−5x+3, g(x)=3x+1 d)f(x)=x3+x2+x+4, g(x)=2x+5

qwerty: a) x³−3x=x x³=4x x²=4 x=2 lub x=−2

fruu: b) ¹₃x³+x+2 = 4x+2 x³+3x+6=12x+6 x³+3x=12x x³=9x x²=9 x=3 lub x=−3

fruu: 4x³−x²−5x+3 = 3x+1 4x³−x²−8x+2=0 x²(4x−1)−2(4x−1)=0 (x²−2)(4x−1)=0 x²−2=0 lub 4x−1=0 x²=2 4x=1 x=√2 lub x=−√2 x=¹₄

fruu: x³+x²+x+4 = 2x+5 x³+x²−x−1=0 x²(x+1)−1(x+1)=0 (x²−1)(x+1)=0 x²−1=0 lub x+1=0 x²=1 x=−1 x=1 lub x=−1