wielomiannyyyyyy
seba: zadanie na wielomianach:
(x−1)3+(2x+3)3=27x3+8
10 mar 21:34
Eta:
można tak:
a3+b3= (a+b)(a2−ab+b2)
L= (x−1+2x+3)*[(x−1)2−(x−1)(2x+3)+(2x+3)2] = ( 3x+2)(3x2+9x+13)
P=(3x+2)(9x2−6x+4)
(3x+2)(3x2+9x+13) −(3x+2)(9x2−6x+4)=0
( 3x+2)( −6x2+15x+9)=0
3x+2=0 v x2−5x −3=0 Δ= 49 √Δ=7
x = −23 v x= 3 v x= −12
10 mar 21:54
seba: dzięki wielkie Eta!
10 mar 22:01