| 4n | ||
an= | ||
| 3n |
| 4n+1 | 4*4n | |||
an+1= | = | |||
| 3n+1 | 3*3n |
| 4*4n | 3n | 4 | ||||
U{an+1{an}= | {* | = | >1 ciąg rosnący | |||
| 3*3n | 4n | 3 |
| 4*4n | 4n | 4*4n | 3*4n | |||||
an+1−an= | − | = | − | = | ||||
| 3*3n | 3n | 3*3n | 3*3n |
| 4n | 1 | 4n | 1 | 4 | ||||||
= | = | * | = | *( | )n | |||||
| 3*3n | 3 | 3n | 3 | 3 |
| 4 | ||
Teraz wniosek taki że | >1 więc ciąg rosnący | |
| 3 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
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| Twój nick | |