qew
witold: ∫x12 lnx2 dx
f(x) = x12
g(x) = 2/x
g'(x) = lnx2
f'(x) = 12x11
x12 *2/x − ∫12x11 * 2/x
czemu mi zle wychodzi co robie zle
16 mar 18:41
wredulus_pospolitus:
| 2 | | 2 | | 2 | |
g(x) = |
| to g'(x) = − |
| a jakbyś chciał g(x) = ln (x2) to g'(x) = |
| |
| x | | x2 | | x | |
16 mar 19:40
wredulus_pospolitus:
| x13 | |
więc jak już to f'(x) = x12 −> f(x) = |
| |
| 13 | |
16 mar 19:41