| 1 | √3 | √3 | |||
cos5x− | sin5x= | ||||
| 2 | 2 | 2 |
| π | √3 | |||
cos(5x+ | )= | |||
| 3 | 2 |
| π | ||
α=5x+ | ||
| 3 |
| √3 | ||
cosα= | ⇔ | |
| 2 |
| π | ||
α=± | +2kπ | |
| 6 |
| π | π | π | π | |||||
5x+ | = | +2kπ lub 5x+ | =− | +2kπ | ||||
| 3 | 6 | 3 | 6 |
| π | π | π | π | |||||
5x= | − | lub 5x=− | − | po obliczeniu sprawdzasz czy x∊<0;π/2> | ||||
| 6 | 3 | 6 | 3 |
| π | π | π | π | |||||
5x= | − | +2π lub 5x=− | − | +2π obliczasz x i sprawdzasz czy x∊<0;π/2> | ||||
| 6 | 3 | 6 | 3 |