granica
Kuba152: Oblicz granicę:
lim n√(4n−14n+1)(3n+2)2
n−>∞
Pod tym pierwiastkiem jest (4n−14n+1)(3n+2)2
9 lis 15:07
chichi:
| | 4n−1 | |
[( |
| )(3n+2)2]1/n = |
| | 4n+1 | |
| | 1 | |
= [(1+ |
| )(4n+1)/(−2)]−2(9n+12+4/n)/(4n+1) → e−18/4 = e−9/2 |
| | | |
9 lis 15:23
Kuba152: Dziękuję Ci bardzo chichi!
9 lis 15:28