Siemka, pomoże ktoś obliczyć granice?
Michał : Lim √n (√n+1 − √n)
n→+∞
8 gru 09:57
janek191:
| | √n* ( n +1 − n) | |
an = √n*( √n +1 − √n) = |
| = U{ √n}{√n +1 + |
| | √n +1 + √n | |
√n}=
= U{1}{
8 gru 10:41
janek191:
| | √n | | 1 | |
= |
| = |
| |
| | √n+1 + √n | | √1 +1n + 1 | |
więc
n→
∞
8 gru 10:44
janek191:
a =
√n +1 b =
√n
Korzystamy z wzoru
8 gru 13:09