| 24 | π | π | ||||
Oblicz wartość wyrażenia sin4α − cos4α, jeśli sin2α = | i α∊( | , | ) | |||
| 25 | 4 | 2 |
| 24 | ||
sin 2α =2 sin α*cos α = | / : 2 | |
| 25 |
| 12 | ||
sin α*cos α = | ||
| 25 |
| 12 | 12 | |||
cos α = | : sin α = | |||
| 25 | 25 sin α |
| 7 | ||
sin4α−cos4α=(sin2α+cos2α)(sin2α−cos2α)= −cos(2α)= −√1−sin2(2α)= − | ||
| 25 |