| sin2x | ||
Oblicz ∫ | dx | |
| sin4x+cos4x |
| cos2(2x) + 1 | ||
sin4x + cos4x = | ||
| 2 |
| sin2x | ||
∫ | dx= | |
| sin4x+(1−sin2x)2 |
| 2sinxcosx | ||
∫ | dx | |
| 2sin4x−2sin2x+1 |
| 1 | 2 | |||
∫ | dt=∫ | dt | ||
| 2t2−2t+1 | 4t2−4t+2 |
| 2 | ||
∫ | dt = arctg(2t−1)+C | |
| 1+(2t−1)2 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |