| lim | 2n2−cos3n | ||
| n→∞ | 3n2−2n+1 |
niech:
an=(2n2−2)/(3n2−2n+2)
bn=(2n2+2)/(3n2−2n)
co mozesz powiedziec o tych ciagach w kontekscie danego ciagu?
| 2n2 | cos(3n) | |||
lim n→∞ ( | − | ) | ||
| 3n2−2n+1 | 3n2−2n+1 |
| 2n2 | 2 | |||
lim n→∞ ( | )= | |||
| 3n2−2n+1 | 3 |
| 1 | 1 | |||
lim n→∞(cos(3n))* | =0 ponieważ |cos(3n)|<1 i ciąg | →0 | ||
| 3n2−2n+1 | 3n2−2n+1 |