| (x+1) | ||
x−> +∞ ( | )2x | |
| (x−2) |
| 3 | ||
(x+1)/(x−2)=1+ | ||
| x−2 |
| 3 | 2x | |||
= lim[ (1 + | )x − 2] | = (e3)2 = e6 | ||
| x − 2 | x − 2 |
| x+1 | x−2+3 | x−2 | 3 | 3 | |||||
= | = | + | = 1+ | ||||||
| x−2 | x−2 | x−2 | x−2 | x−2 |
| x +1 |
| ||||||||||||
f(x) = ( | )2x = [ | ]2 | |||||||||||
| x − 2 |
|
| e | ||
lim f(x) = [ | ]2 = e6 | |
| e−2 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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