Oblicz granicę
Jeszcze student: Oblicz granicę:
lim x−>1 (1+sinπx)ctgπx
23 lis 09:03
piotr: | | 1 | |
limx−>1(1+sinπx)ctgπx = limx−>1(1+ |
| )cosπx/sinπx = |
| | 1/sinπx | |
| | 1 | |
=limx−>1[(1+ |
| )1/sinπx]cosπx= e−1 |
| | 1/sinπx | |
23 lis 09:58
Jeszcze student: To ma sens, dzięki bardzo!
23 lis 10:21