n | ||
an = (3n+1)[ln(n) − ln(n+2)] = ln( | )3n+1 = | |
n+2 |
−2 | ||
= ln[(1 + | )(n+2)/−2(−6n − 2)/(n+2)] → − 6 | |
n+2 |
n+2 | n+2 | 2 | ||||
(3n+1)(ln n − ln (n+2) ) = − (3n+1) ln | = − ln | − 3 ln (1+ | )n | |||
n | n | n |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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