| 4n + √4n2 − 1 | ||
f (n)= | , oblicz f(1)+f(2)+...+f(40)=? | |
| √2n+1+√2n−1 |
| 4n + 2√4n2 − 1 | ||
f(n) = | ||
| √2n+1 + √2n−1 |
| a2 + b2 + ab | a3−b2 | 1 | ||||
f(n) = | = | = | [ (2n+1)3/2 − (2n−1)3/2 ] | |||
| a+n | a2−b2 | 2 |
| 1 | ||
suma = | (813/2 − 13/2) =13 | |
| 2 |
zgadza się.
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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