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oblicz ja: sin11/3π sin(2π+5π/3)=sin5/3 ?
28 cze 21:23
Mila:
 5π 5π π 
sin(2π+
)= sin
=sin(2π−
)= ..?
 3 3 3 
28 cze 22:09
on: sin(11π/3)= sin(4π−(π/3)) = sin(−π/3)= −sin(π/3)= −√3/2
28 cze 22:10