| ||||||||
∑k | =24n−2+ (−1)n22n−1 | |||||||
| 1 | 1 | ||
+ | =1 | ||
| 1+i | 1−i |
| 1 | d | ||
suma = | [(1+x)4n − (1−x)4n − i(1+ix)4n + i(1+ix)4n] | ||
| 4*4 | dx |
| n | ||
= | [(1+x)4n−1 + (1−x)4n−1 + (1+ix)4n−1 + (1−ix)4n−1] , x=1 | |
| 4 |
| n | ||
= | [ 24n−1 + (1+i)4n−1 + (1−i)4n−1]=n[24n−3 + (−1)n22n−2] | |
| 4 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |
