oblicz:
illusion: cos150° * sin120° + 2tg135° =
2sin60° − sin2 47° − cos2 43° =
17 mar 21:22
Leszek: b) 2sin 60° −( sin247° + cos243° ) = ......czy tam nie powinno byc drugi sin243° ? ?
17 mar 21:26
janek191:
cos 150
o * sin 120
o + 2 tg 135
o = cos( 90
o + 60
o)*sin( 90
o + 30
o) + 2 tg(90
o + 45
o) =
| | √3 | | √3 | | 3 | | 3 | |
= −sin60o *cos30o + 2*(−ctg45o) = − |
| * |
| − 2*1 = − |
| − 2 = −2 |
| |
| | 2 | | 2 | | 4 | | 4 | |
17 mar 21:58