| cos20(1+tg210) | ||
Udowodnij, że | =1 | |
| 1−tg210 |
| cos2a + sin2a | cos2a | |||
Licznik = cos2a(1 + tg2a) = cos2a | = | = | ||
| cos2a | cos2a |
| cos2a − sin2a | ||
= | = 1 − tg2a = Mianownik | |
| cos2a |
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L=cos2* | = | ||||||||||
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=cos2* | = | |||||||
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| cos2 | cos2 | |||
= | = | =1 | ||
| cos21−sin21 | cos2 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
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| Twój nick | |