| ln(n−1) | ||
lim n→∞ | ||
| ln(n) |
| n | n | ||||||||||
=lim | =lim | =lim | =1 | |||||||||
| n−1 | n(1−1n) |
| ln(n−1) | ln(n−1) − ln n + ln n | ln(1−1/n) | |||
= | = | + 1 →1 | |||
| ln n | ln n | ln n |
| n | ||
A czy granice limn→∞ | tez moge obliczyc z de Hospitala ? | |
| n−1 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |