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ertert: √10−4*√6/(2−√6)+√8−2*√7/(√7−1)
7 lis 18:40
6latek: Ogolnie
| | A+C | | A−C | |
√A±√B= √ |
| +/− √ |
| |
| | 2 | | 2 | |
gdzie
A
2−B=C
2
√10−4√6=
√10−√96
A
2−B= 100−96=4=C
2 to C=2
| | 10+2 | | 10−2 | |
√10−√96= √ |
| − √ |
| = √6−√4= √6−2 |
| | 2 | | 2 | |
7 lis 18:51
Eta:
(2−
√6)
2= 10−4
√6 to
√(2−√6)2= |2−
√6|= −(2−
√6)
(
√7−1)
2=8−2
√7 to
√(√7−1)2= |
√7−1|=
√7−1
| | −(2−√6) | | √7−1 | |
W= |
| + |
| = −1+1=0 |
| | (2−√6) | | √7−1 | |
7 lis 20:10