granica
123: | | x2−1 | |
Oblicz lim x→ −1 |
| |
| | x2+x | |
| | x2+2x−8 | |
oblicz lim x−> 2 |
| |
| | x2−4 | |
24 paź 19:05
janek191:
1)
| | (x −1)*(x + 1) | | x−1 | | 1 | |
f(x) = |
| = |
| = 1 − |
| |
| | x*(x + 1) | | x | | x | |
więc
lim f(x) = 2
x→ −1
24 paź 19:08
abcd: x2−1= (x−1)(x+1)
x2+x= x(x+1)
x2+2x−8
x1+x2= −2
x1*x2=−8 to x1= x2=
x2−4=(x+2)(x−2)
24 paź 19:09
janek191:
24 paź 19:10